How can I calculate the oxidation number for FeSO4?

The oxidation number of FeSO4 is calculated as 0, it is a neutral compound.

The first step is to Identify the oxidation number of each element present in the compound.

Oxidation number of S is +6.

Oxidation number of Fe is +2.

Oxidation number of O is (-2 ✕ 4) = – 8

When all the oxidation number of the compound is added, it gives

(+2) + (+6) + (-8) = 0

(+8) – 8 = 0.

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