How do I calculate the bond order for H2- and H2+?

One half the difference between the number of electrons present in the bonding and the anti-bonding orbitals is bond order
Bond order (B.O) =1/2(Nb−Na)

Bond order of H2−
Total number of electrons =2+1=3
Molecular orbital electrons is configuration
[σ(1s)]2[σ∗(1s)]1

Bond order =1/2(2−1)=21

bond order of H2= 1/2 (2-0) = 1,

which means H2has only one bond. The antibonding orbital is empty.

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