We have to evaluate \(\frac{1+i}{1-i}\)
Solution
\(\frac{1+i}{1-i}\)We will multiply Numerator and Denominator by ( 1 +i)
\(\frac{1+i}{1-i} X \frac{1+i}{1+i}\)= \(\frac{1+2i+i^{2}}{1-i^{2}}\)
We know that i2= -1. On substituting in above equation we get
=\(\frac{1+2i-1}{1-(-1)}\)
=\(\frac{2i}{2}\)
= i
Answer
\(\frac{1+i}{1-i}\)= i