How do you evaluate log 0.01?

log_0.01 10

Let log_0.01 10 = x

(0.01)x = 10

(10^-2)^x = 101

10^-2x = 10¹

-2x = 1

We get,

x = (- 1 / 2)

Hence, the value of x is (-1 / 2)