Question

How do you find bond order of ${{\mathrm{NO}}_3}^{-}$?

Answer 1

Bond order:

1. It is defined as the number of electrons involved in bonding between two atoms in a molecule.
2. It is used to determine the stability of a chemical bond. The greater the bond order, the stronger the chemical bond.
3. The bond order of ${{\mathrm{NO}}_3}^{-}$ can be calculated using its lewis dot structure as shown:
4. 
5. Bond order$=\frac{\mathrm{total}\mathrm{number}\mathrm{of}\mathrm{bonds}}{\mathrm{number}\mathrm{of}\mathrm{bonds}\mathrm{group}}$
6. In ${{\mathrm{NO}}_3}^{-}$ we have four $\mathrm{N}-\mathrm{O}$ bonds and three bond groups.
7. So, bond order $=\frac{4}{3}\Rightarrow 1.33$

Therefore, the bond order of ${{\mathrm{NO}}_3}^{-}$is $1.33$