How do you find the derivative of y = tan^2(x)?

We have to find the derivative of y = tan2x

Solution

Let us differentiate using chain rule

Chain rule states that

y = f(g(x))

dy/dx= f'(g'(x)) + g'(x)

Given y = tan2x which can also be expressed as tan x2

dy/dx = 2 tan x X dy/dx(tan x)

= 2 tanx sec2x

dy/dx = 2 sec2x tan x

Answer

The derivative of y = tan2x is dy/dx = 2 sec2x tan x

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