Question

How do you find the exact square root of $39$?

Answer 1

Solve for the square root.

The prime factorization of $39$ is

$$\begin{gathered} 39=3X13 \\ \sqrt{39}=\sqrt{3}x\sqrt{13} \end{gathered}$$

On substituting the root values we get

$$\begin{gathered} \sqrt{39}=1.732X3.606 \\ \sqrt{39}=6.245 \end{gathered}$$

Hence, the required value of root $39$ is $6.245$