Question

How do you find the value of $cot45°$?

Answer 1

Calculate the value of trigonometric ratio at given angle:

Let $x$ be the value of $cot45°$.

$\therefore x=cot45°$

$=\frac{\cos 45°}{\sin 45°}$ $[\because co\mathrm{t\theta }=\frac{co\mathrm{s\theta }}{si\mathrm{n\theta }}]$

$=\frac{\frac{1}{\sqrt{2}}}{\frac{1}{\sqrt{2}}}$ $\left[\because sin45°=\frac{1}{\sqrt{2}};cos45°=\frac{1}{\sqrt{2}}\right]$

$=1$

Hence, the value of $\mathit{c}\mathit{o}\mathit{t}\mathbf{}\mathbf{45}\mathbf{°}$ is $\mathbf{1}$.