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Question

How do you solve 2x2-7x+3=0 by completing the square.


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Solution

Compute the roots of the quadratic equation.

Given: 2x2-7x+3=0

2(x2-72x)+3=0

Making a perfect square by adding and subtracting 2742

2x2-72x+742-2742+3=0

2x-742-498+3=0

2x-742=258

x-742=2516

x-74=±54

x=±54+74

x=3or12

Hence, the roots of 2x2-7x+3=0 are 3 and 12.


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