How do you use log tables to find logarithm and the antilogarithm of 445.66?

In the log table, it contains numbers like 6484 and 6493 respectively in the columns of 5 and 6 445.66 is about 2/3 of the way between 445 and 446 ,

we add (6493−6484)⋅2/3=6 to 6484 to get 6490

Hence, the logarithm of 4.4566 is approximately 0.6490

Then: log(445.66)=log(100⋅4.4566) =log(100)+log(4.4566)≈2+0.6490=2.6490

Antilog of 445.66 In the antilog table against 0.66 in the 0 columns, we identify 4571

That refers 100.66≈4.571 Therefore, 10 445.66 ≈4.571×10 445

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