How many are two-digit numbers divisible by 6?

Answer:

First two-digit number divisible by 6 = 12

Last two-digit number divisible by 3 = 96

An arithmetic progression (A.P) is a progression in which the difference between two consecutive terms is constant.

A.P = 12,18,24,30…….96

here

First term (a) = 12

Common difference (d) = 6

Let us consider there are n numbers then

an = 96

a + (n – 1)d = 96

12 + (n – 1)6 = 96

12 + 6n – 6 = 96

6n = 90

n = 15

∴ Two-digit numbers divisible by 6 = 15

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