Question

How many elements would a period can maximum comprise of if there were ten periods in the periodic table?

Answer 1

Number of elements in a period

• The formula to determine the number of elements in a given period is if n is even=$\frac{{(n+2)}^2}{2}$, if n is odd= $\frac{{(n+1)}^2}{2}$ where n is the period number.
• Given that there are ten periods So n=$10$.
• Hence by substituting the value of n in the even formula we get 10 periods

$$\begin{gathered} \frac{{(10+2)}^2}{2} \\ =\frac{144}{2} \\ =72 \end{gathered}$$

• Number of elements= $72$

Therefore, The number of elements in the given period= $72$