How many grams of conc.nitric acid solution should be used to prepare 250ml of 2m hno3? given the concentrated acid is 70% hno3

To prepare 250mL of 2M HNO3,

the required no of moles = 250/1000 = 0.5

Mass = no of moles*molar mass

Molar mass of HNO3 = 63.01

Therefore mass= 0.5*63.01 = 31.5g of HNO3

In 100g of solution 70g of HNO3 is present

so 1g = 100/70

31.5g will be present in (100/70)*31.5 = 45g


Free Class