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Question

How many grams of conc. Nitric acid(HNO3) solution should be used to prepare 250ml of 2M(HNO3)?Given the concentrated acid is 70%(HNO3).


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Solution

Step 1: Given Data

  • The concentrated acid is 70% (HNO3).
  • 2MHNO3 indicates 2 moles of (HNO3) is dissolved in 1000ml of solution.
  • Molecular weight of HNO3=63grams.

Step 2: Calculation of number of moles of Nitric acid (HNO3)

Molarity=NumberofmolesofsoluteVolumeofsolution

Number of moles= Molarity× Volume of Solution

In 250ml of solution the number of moles is:

250×21000=0.5moles

Step 3: Calculation of weight of Concentrated HNO3

Weight of (HNO3)= number of moles of solute× molar mass

After substituting the values Weight of Conc. (HNO3)= 0.5×63=31.5g

70% weight by means 70g (HNO3) is present in 100g of solution.

Mass of (HNO3) required is

(10070)×31.5=45gm

Therefore, 45g are required to prepare 250ml of 2M (HNO3)..


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