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Question

How many grams of dibasic acid (molar mass 200) should be present in 100ml of aqueous solution to give 0.1N.


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Solution

Step 1: Given data

  • Normality of dibasic acid=0.1N
  • n-factor of dibasic acid= 2
  • Molar mass of dibasic acid=200gm
  • Volume= 100ml

Step 2: Calculation of number of moles

Number of moles= Molarity× Volume(in Litres)

Number of moles

0.05×0.1

=0.005

Step 3: Calculation of weight of dibasic acid

Number of moles= given weight/molecular weight

After substituting the values we get

0.005=givenweight200givenweight=0.005×200givenweight=1gm

Therefore, 1gram of Dibasic acid should be present in 100ml of the aqueous solution to prepare a 0.1N solution.


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