Given:
P= 0.987 bar
K= 76.48 Kbar= 76480
As per the Henry’s law
P=Kx
x is the mole fraction
K is the henry’s law constant
P is the pressure in atm.
mole fraction of N2 = x / (x = 55.5)
Hence
0.987= 76480 * x / (x = 55.5)
x = 0.7 millimole
Given:
P= 0.987 bar
K= 76.48 Kbar= 76480
As per the Henry’s law
P=Kx
x is the mole fraction
K is the henry’s law constant
P is the pressure in atm.
mole fraction of N2 = x / (x = 55.5)
Hence
0.987= 76480 * x / (x = 55.5)
x = 0.7 millimole
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