The metal ion V3+ is in +3 oxidation state, with configuration d2, and the hybridization of metal ion orbitals for ligand bond is d2sp3, where the number of unpaired electrons in [V(H2O)6]3+ is 2.
Explanation
For V, the neutral atom would have two 4s and three 3d electrons. V3+ has 3 electrons stripped from the V neutral atom. Leaving two electrons in 4s and removing the three 3d electrons leave the ion in the lowest (and most stable) possible energy state.
