How many unpaired electrons are there in [V(H2O)6]3+?

The metal ion V3+ is in +3 oxidation state, with configuration d2, and the hybridization of metal ion orbitals for ligand bond is d2sp3, where the number of unpaired electrons in [V(H2O)6]3+ is 2.

Explanation

For V, the neutral atom would have two 4s and three 3d electrons. V3+ has 3 electrons stripped from the V neutral atom. Leaving two electrons in 4s and removing the three 3d electrons leave the ion in the lowest (and most stable) possible energy state.

Was this answer helpful?

 
   

0 (0)

(0)
(2)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question