Question

How to calculate the equivalent weight of ferrous ammonium sulphate?

Answer 1

Step 1: Equivalent weight formula:-

The equivalent weight of any element can be calculated using the formula;

$\mathrm{Equivalent}\mathrm{weight}=\frac{\mathrm{Molecular}\mathrm{weight}}{\mathrm{X}}$

Where, $\mathrm{X}=$valence factor,

The valence factor for acids and bases is represented as the number of ${\mathrm{H}}^{+}\mathrm{and}{\mathrm{OH}}^{-}$ ions they release in the solution, respectively.

Step 2: Calculation of the equivalent weight for ferrous ammonium sulfate:-

The chemical formula of Ferrous ammonium sulfate is ${\mathrm{FeSO}}_4.{\left({\mathrm{NH}}_4\right)}_2{\mathrm{SO}}_4.6{\mathrm{H}}_2\mathrm{O}$.

In Ferrous ammonium sulfate, there are no charged ions present in the molecule.

As only a single entity is present in the solution the valence factor in the case of ferrous ammonium sulfate is $\mathrm{X}=$1.

Therefore, $\mathrm{Equivalent}\mathrm{weight}=\frac{\mathrm{Molecular}\mathrm{weight}}{1}$

or, the given equivalent weight = molecular weight of Ferrous ammonium sulfate = $392.13\mathrm{g}{\mathrm{mol}}^{-1}$.

Hence, the calculated equivalent weight of copper sulfate is found to be $392.13\mathrm{g}{\mathrm{mol}}^{-1}$.