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Question

How to find tan-π?


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Solution

Find the required value:

tan(-π)=sin(-π)cos(-π)[tanx=sinxcosx]tan-π=-sin(π)cos(π)[sin(-x)=-sin(x)andcos(-x)=cos(x)]tan(-π)=-(0)-(1)[sin(π)=0andcos(π)=-1]tan(-π)=0

Therefore, the required value is tan(-π)=0.


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