How to find tan-π?
Find the required value:
tan(-π)=sin(-π)cos(-π)[∵tanx=sinxcosx]tan-π=-sin(π)cos(π)[∵sin(-x)=-sin(x)andcos(-x)=cos(x)]tan(-π)=-(0)-(1)[∵sin(π)=0andcos(π)=-1]tan(-π)=0
Therefore, the required value is tan(-π)=0.
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