Question

How to prepare a 1N $\mathrm{HCl}$solution in 100 ml?

Answer 1

Preparation of 1N $\mathrm{HCl}$ solution in 100 ml

We know that the Normality of $\mathrm{HCl}$ is 12N

According to the formula

$N_1{V}_1=N_2{V}_2$

$N_1=12N$

$V_1=?$

$$\begin{gathered} N_2=1N\left(Given\right) \\ {V}_2=100ml \end{gathered}$$

Substituting the values in the above formula we get,

$$\begin{gathered} 12X{V}_1=1X100 \\ {V}_1=\frac{100}{12} \\ {V}_1=8.33mL \end{gathered}$$

Therefore, If we add 8.33mL to 100 L of water we get 1 N $\mathrm{HCl}$.