Question

If $(6,k)$ is a solution of the equation $3x+y-22=0$, then the value of $k$ is?

Answer 1

Find the value of $k$

Given $(6,k)$ is a solution of the equation $3x+y-22=0$.

This means that, $(6,k)$ satisfies the equation $3x+y-22=0$.

Now, put $x=6$ and $y=k$ in the given equation. We get,

$\Rightarrow 3\left(6\right)+k-22=0$

$\Rightarrow 18+k-22=0$

$\Rightarrow k-4=0$

$\Rightarrow k=4$

Hence, the value of $k$ is $4$.