If A is an invertible matrix of order 2, then det (A-1) is equal to

(a) det (A) 

(b) 1/det(A) 

(c) 1 

(d) 0

Solution:

We know AA-1 = I

Take determinant on both sides

|AA-1| = |I|

|A| |A-1| = 1

=> |A-1| = 1/|A|

Hence option b is the answer.

Was this answer helpful?

 
   

5 (1)

(0)
(0)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question