If N Arithmetic Means Are Inserted Between 1 And 31 Such That Ratio Of First And Nth Mean Is 3:29, Then What Is The Value Of N?

The first mean = 1 + d

The nth mean = 1 + nd

ration =[latex] \frac{3}{29}[/latex] [latex]\frac{1 + d}{1 + nd} \Rightarrow \frac{3}{29}[/latex]—[1]

31 = 1 + (n + 1)d—[2]

By solving both the equations [1] and [2], we get:

n = 14

Therefore, the value of n is 14.

Explore more such questions and answers at BYJU’S.

Was this answer helpful?

 
   

0 (0)

(0)
(0)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question