If Rotational Kinetic Energy Is 50% Of Total Kinetic Energy Then The Body Will Be


As given:

Rotational Kinetic Energy = Translational Kinetic Energy

\(\Rightarrow \frac{1}{2} I\omega ^{2} = \frac{1}{2} mv ^{2}\)

As v =\( \omega r \) \(\Rightarrow I * \omega ^{2} = m * \omega ^{2}r^{2}\\\Rightarrow I = mr^{2}\)

Therefore, if rotational kinetic energy is 50% of total kinetic energy, then the body will be a ring.

Explore more such questions and answers at BYJU’S.

Was this answer helpful?


0 (0)


Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *




Free Class