If sinA=13 and A+B=90° then find cosB?
Computing the required value using trigonometric identities
Given:
sinA=13A+B=90°
It can be written as,
A=90°-B
Taking sin on both sides.⇒sinA=sin90°-B⇒cosB=13[∵sin(90o-θ)=cosθ]
Hence, the value of cosB is 13.
If tan (A - B) = 1√3 and tan (A+B)=√3, 0∘ <(A+B) < 90∘ and A > B then find A and B.