If The Class Intervals Are 10-19, 20-29, 30-39.......Then The Upper Limit Of The First Class Intervals Will Be (A) 19. (B) 19.5. (C) 20. (D) 20.5.

The correct answer is (B) 19.5.

Given C.I= 10-19, 20-29, 30-39…..

These class intervals are not continuous. To make them continuous, we need to find the mean of the upper limit of first-class and the lower limit of second class.


Mean = [latex]\frac{19 + 20}{2} = 19.5[/latex]

Hence, 19.5 is the upper limit of the first-class and lower limit of the second class for the continuous class intervals.

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