Question

If the concentration of glucose in blood is $0.9\mathrm{g}{\mathrm{L}}^{-1}$, what will be the molarity of glucose in blood?

• A. $5\mathrm{M}$
• B. $0.5\mathrm{M}$
• C. $0.005\mathrm{M}$
• D. $50\mathrm{M}$

Answer 1

The correct option is C

$0.005\mathrm{M}$

Explanation:

Step 1: Analyzing the given data:

The concentration of glucose in blood = $0.9\mathrm{g}{\mathrm{L}}^{-1}$

Now, the Mass of glucose in$1\mathrm{L}=0.9\mathrm{g}$

We also know that the molecular mass of Glucose $=180\mathrm{g}{\mathrm{L}}^{-1}$

Step 2: Calculation of no. of moles of glucose

We can calculate No. of moles as;

$$\begin{gathered} \mathrm{n}=\frac{\mathrm{given}\mathrm{mass}}{\mathrm{molar}\mathrm{mass}} \\ \mathrm{n}=\frac{0.9\mathrm{g}}{180\mathrm{g}{\mathrm{mol}}^{-1}} \\ \mathrm{n}=5\mathrm{x}{10}^{-3}\mathrm{mol} \end{gathered}$$

Step 3: Calculation of molarity of glucose

The Molarity of glucose is calculated as;

$\mathrm{Molarity}=\frac{\mathrm{no}.\mathrm{of}\mathrm{moles}}{\mathrm{Volume}\mathrm{in}\mathrm{litres}}$

$$\begin{gathered} \mathrm{M}=\frac{5\mathrm{x}{10}^{-3}}{1} \\ \mathrm{M}=0.005\mathrm{M} \end{gathered}$$

Hence, for the given concentration of glucose, the molarity of glucose in the blood is found to be $0.005\mathrm{M}$.