# If The Overbridge Is Concave Instead Of Being Convex. What Will Be The Thrust On The Road At Lowest Position?

Let the normal reaction (thrust) applied by the bridge be N.

Circular motion equation : mar= N − mg

Therefore,

$$\frac{mv^{2}}{r} = N – mg\\\Rightarrow N = \frac{mv^{2}}{r} + mg$$

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