Given X+1/X =3.
Therefore (x+1/x)^2=x^2+1/x^2+2 =9, so x^+x^2=7.
Similarly,x^3+1/x^3=18
Also,x^5+1/x^5 = (x^2+1/x^2) * (x^3+1/x^3)
=x^5+1/x^5+x+1/X= 18×7=126.
Hence x^5+1/x^5=126-3=123.
Given X+1/X =3.
Therefore (x+1/x)^2=x^2+1/x^2+2 =9, so x^+x^2=7.
Similarly,x^3+1/x^3=18
Also,x^5+1/x^5 = (x^2+1/x^2) * (x^3+1/x^3)
=x^5+1/x^5+x+1/X= 18×7=126.
Hence x^5+1/x^5=126-3=123.
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