If you are given a force of magnitude $25 N$ acting on a body of mass $2 kg$ increases its kinetic energy from $100 J$ to $200 J$ . The displacement of the body during this interval is?

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Solution

Step 1: Given data
$F o r c e = 25 N, M a s s = 2 k g$
$F i n a l k i n e t i c e n e r g y = 200 J I n i t i a l k i n e t i c e n e r g y = 100 J$
Step 2: Formula used
The work-energy theorem states that the net work done by the forces on an object equals the change in its kinetic energy.
$∆ K E = K E_{f} - K E_{i} [w h e r e K E_{f} = f i n a l k i n e t i c e n e r g y, K E_{i} = i n i t i a l k i n e t i c e n e r g y] W = F \times d [w h e r e W = w o r k, F = d o r c e, d = d i s p l a c e m e n t]$
Step 3: Kinetic energy
We know the body's initial and final kinetic energy, thus we can calculate the kinetic energy change.
$∆ K E = K E_{f} - K E_{i} ∆ K E = 200 J - 100 J ∆ K E = 100 J$
Step 4: Calculating displacement
We can now calculate the displacement of the body during that interval using the work done formula.
$W = F \times d W = 25 N \times d 100 J = 25 N \times d [W = K . E] d = \frac{100 J}{25 N} d = 4 m$
Hence, the displacement of the body is $4 m$ .

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If you are given a force of magnitude 25N acting on a body of mass 2kg increases its kinetic energy from 100J to 200J. The displacement of the body during this interval is?

If you are given a force of magnitude $25 N$ acting on a body of mass $2 kg$ increases its kinetic energy from $100 J$ to $200 J$ . The displacement of the body during this interval is?