In 2Na(S) + Cl2 → 2 NaCl (S): The oxidising agent is chlorine.
According to the new concept, loss of electrons is oxidation and the agent that helps in oxidation is the oxidizing agent which is chlorine in this case.
- In the above given reaction sodium metal (Na) reacts with chlorine gas (Cl2) to produce sodium chloride (NaCl).
- Sodium’s oxidation number rises from 0 on the reactant’s side to +1 on the product’s side, meaning that sodium is being oxidised.
- The oxidation number of chlorine, on the other hand, decreases from 0 in the reactants to -1 in the products, indicating that chlorine is being reduced.