In a magnetic field of 0.05T, the area of a coil changes from 101cm2 to 100cm2 without changing the resistance which is 2 Ω. The amount of charge that flow during this period is

a) 2.5 x 10-6 C

b) 2 x 10-6 C

c) 10-6 C

d) 8 x 10-6 C

Answer: a) 2.5 x 10-6 C

Solution:

Magnetic flux, Φ = B.A

Change in flux, dΦ = B.dA

= (0.05) (101 – 100) x 10-4

= 5 x 10-6 Wb

Charge dQ = dΦ/R

= 5 x 10-6/2

= 2.5 x 10-6 C

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