Question

In a single throw of a die, what is the probability of getting a number more than $4?$

Answer 1

Compute the required probability.

The formula of probability:

$\text{Probability of an event to happen=}\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

Since the set of numbers present on a die is $\{1,2,3,4,5,6\}$.

Therefore, the total number of outcomes is $6$.

Since the set of numbers greater than $4$ for a die is $\{5,6\}$.

Therefore, the number of outcomes in favour is $2$.

So, the required probability $P$ will be given by:

$$\begin{gathered} P=\frac{2}{6} \\ \Rightarrow P=\frac{1}{3} \end{gathered}$$

Therefore, the probability of getting a number more than $4$ is $\frac{1}{3}$.