Question

Is $128$ a perfect cube.

Find its cube root.

Answer 1

Check whether $128$is a perfect cube or not

Upon factorizing $128$ we get

$$\begin{gathered} 128=2x2x2x2x2x2x2 \\ 128=(2x2x2)x(2x2x2)x\left(2\right) \end{gathered}$$

Upon taking cube root on both sides we get

$\sqrt[3]{128}=2\times 2\times 2^{\frac{1}{3}}$

$\Rightarrow \sqrt[3]{128}=4\sqrt[3]{2}$

Hence $128$ is not a perfect cube.