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Question

Lowering in vapor pressure is highest for:


A

0.2MUrea

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B

0.1MBaCl2

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C

0.1MMgSO4

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D

0.1MGlucose

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Solution

The correct option is B

0.1MBaCl2


The correct option is (B):-

Explanation for the correct answer:

Step 1: Finding the relation between the Lowering of Vapor Pressure and Van't Hoff factor (i).

P°-PSP°=nBnA=nBWA×MA×i

P°-PSP°=m×mA×i

P=P°-PS=P°×m×mA×i

( where, Pstandsforrelativeloweringinvaporpressure )

Therefore, Pisdirectlyproportionaltom×i

Step 2: Calculating value of m×i for each.

For Urea, i = 1 (non-electrolyte) So, m×i=0.2×1=0.2

For BaCl2, i = 3 (because of 2 Cl- ions and 1 Ba2+ion) So, m×i=0.1×3=0.3

For MgSO4, i = 2 (because of 1 Mg2+ and 1 SO42- ions) So, m×i=0.1×2=0.2

For Glucose, i = 1(non-electrolyte) So, m×i=0.1×1=0.1

Hence, m×i for BaCl2 is highest, so as P (lowering in vapor pressure)

Therefore, the correct option is (B):- 0.1MBaCl2


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