Molarity of 0.1 N of oxalic acid?

Answer: The molarity of oxalic acid solution is 0.05 M.

The chemical formula of oxalic acid = H₂C₂O₄

Normality the of oxalic acid solution = 0.1 N

In the formation of carbon dioxide two electrons are extracted from oxalic acid solution

C2O42-→ 2CO2 + 2e¯

n-factor of oxalic acid = 2

Normality can be calculated using formula

Normality = Molarity × n- factor

Molarity = Normality/n-factor

Molarity = 0.1/2

Molarity = 0.05 M

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