Name the process of conversion of K₂Cr₂O₇ into Cr₂(SO₄)₃

Answer:

Given equation

K₂Cr₂O₇ → Cr₂ (SO₄)₃

It is an example of reduction process.

Let us find the oxidation state of Cr in both K₂Cr₂O₇ and Cr₂ (SO₄)₃

(1) K₂Cr₂O₇ 

2(1) + 2(x) + 7(-2) = 0

2 + 2x – 14 = 0

2x – 12 = 0

2x = 12

x = +6

(2) Cr₂ (SO₄)₃

2(x) + 3(-2) = 0

2x – 6 = 0

2x = 6

x = +3

Oxidation number of Cr changes from +6 in K₂Cr₂O₇ to +3 in Cr₂ (SO₄)₃. So, this is an example of reduction.