Name the process of conversion of K2Cr2O7 into Cr2(SO4)3

Answer:

Given equation

K2Cr2O→ Cr2 (SO4)3

It is an example of reduction process.

Let us find the oxidation state of Cr in both K2Cr2Oand Cr2 (SO4)3

(1) K2Cr2O

2(1) + 2(x) + 7(-2) = 0

2 + 2x – 14 = 0

2x – 12 = 0

2x = 12

x = +6

(2) Cr2 (SO4)3

2(x) + 3(-2) = 0

2x – 6 = 0

2x = 6

x = +3

Oxidation number of Cr changes from +6 in K2Cr2O7 to +3 in Cr2 (SO4)3. So, this is an example of reduction.

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