Question

The number of Fe Atoms in 100g Haemoglobin if it contains 0.33% Fe. (Atomic Mass Of Fe=56) is-

Answer 1

Step 1: Given data

${\mathrm{W}}_{\mathrm{Hb}}=100\mathrm{g}$

${\mathrm{Amount}}_{\left(\mathrm{Fe}\right)}=0.33\%$

Step 2: Calculating the mass of Fe atoms in 100g Hb:

$W_{Fe}=\frac{0.33}{100}\times 100=0.33g$

Step 3: Calculating the number of moles of 0.33g Fe:

$$\begin{gathered} NumberofmolesofIron=\frac{weightofFe}{AtomicMassofFe} \\ {n}_{Fe}=\frac{W_{Fe}}{M_{Fe}}=\frac{0.33}{56}=5.89\times 0^{-3} \end{gathered}$$

Step 4: Calculating the number of Fe atoms in 100g Hb:

$$\begin{gathered} {\mathrm{n}}_{\mathrm{Fe}}=\frac{{\mathrm{W}}_{\mathrm{Fe}}}{{\mathrm{M}}_{\mathrm{Fe}}}=\frac{\mathrm{Number}\mathrm{of}\mathrm{atoms}\mathrm{of}\mathrm{Fe}}{6.022\times {10}^{23}}=5.89\times 0^{-3} \\ \frac{\mathrm{Number}\mathrm{of}\mathrm{atoms}\mathrm{of}\mathrm{Fe}}{6.022\times {10}^{23}}=5.89\times 0^{-3} \\ \mathrm{Number}\mathrm{of}\mathrm{atoms}\mathrm{of}\mathrm{Fe}=5.89\times 0^{-3}\times 6.022\times {10}^{23} \\ \mathrm{Number}\mathrm{of}\mathrm{atoms}\mathrm{of}\mathrm{Fe}=3.54\times {10}^{21} \end{gathered}$$

Therefore, the number of atoms in 100g Hb is $3.54\times {10}^{21}$.