Question

One liter of ${\mathrm{CO}}_2$ is passed through red hot coke. The volume becomes 1.4 litres at same temperature and pressure. The composition of the products is ____.

Answer 1

Step 1: The equation for this reaction can be represented as:

$\underset{1\mathrm{v}}{{\mathrm{CO}}_2}+\underset{1\mathrm{v}}{\mathrm{C}}\to \underset{2\mathrm{v}}{2\mathrm{CO}}$

Let v be the liter of ${\mathrm{CO}}_2$ gives 2v liter of $\mathrm{CO}$.

Hence the remaining volume of ${\mathrm{CO}}_2$ = (1 - v)

Total volume= 1.4 liters (given)

Step 2: The composition of the products:

(1-v) + 2v = 1.4

1 + v= 1.4

v = 0.4 liter

As, $\mathrm{CO}$ = 2v

So, 2 × 0.4= 0.8 liter

And so the Volume of ${\mathrm{CO}}_2$ = 1.4-0.8

= 0.6 lit.

Hence, the composition of the product is 0.8 liters for $\mathrm{CO}$ and 0.6 liters for ${\mathrm{CO}}_2$.