Out of NH3, PH3, AsH3 and SbH3 the most basic hydride is______

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Solution

The basicity of the nitrogen family decreases down the group due to the decrease in the electron density on the central atom.
The order of basicity is given by
$N H_{3} > P H_{3} > A s H_{3} > S b H_{3} \geq B i H_{3}$
Thus the correct answer is $N H_{3}$

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Similar questions

Out of NH₃, PH₃, AsH₃ and SbH₃ the most basic hydride is:

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

Why basicity decreases down the group ?

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