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Question

Peroxy linkage is present in-


  1. H2SO5

  2. H2SO3

  3. H2S2O7

  4. H2SO4

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Solution

The correct option is A

H2SO5


The explanation for the correct option:

Option (A): H2SO5

  • The peroxide bonds in a compound can be calculated by knowing the oxidation number of the central metal in a compound.
  • If the oxidation number of central metal in a compound comes out to be greater than the maximum oxidation state of that central metal then that compound must contain peroxide bonds.
  • In the case of In H2SO5, the oxidation state of sulfur can be calculated as:
    +2+x+(−10)=0x=+8
  • But Sulfur has a maximum oxidation state of +6. hence, there will be one peroxide bond present in the given molecule, which can be given as

The explanation for the incorrect option:

Option (B): H2SO3

  • H2SO3 has no peroxide bond present in the molecule.
  • Hence, the option is the incorrect one.
H2SO3 Lewis Structure & Compound Name | What is H2SO3? - Video & Lesson  Transcript | Study.com

Option (C):H2SO4

  • There is no peroxide bonding present in the H2SO4molecule.
  • Thus, the given option does not represent the correct option.
Sulfuric Acid Formula & Structure | How is Sulfuric Acid Made? | Study.com

Option (D): H2S2O7

  • H2S2O7 has no peroxide bond present in the molecule.
  • Hence, the given option does not coincide with the correct option.
Draw the structure of the following H2S2O7 class 12 chemistry CBSE

Hence, peroxy linkage is present in H2SO5, option (A) is the correct answer.


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