Prove that : 4?5 squar root of 3 is irrational.

Answer:

Let us assume 4 – 5√3 be a rational number.

⇒ 4 – 5√3 = a/b

Where a, b are integers and b ≠ 0.

⇒ – 5√3 = a/b -4

⇒ √3 = 4/5 – a

LHS is √3 which is an irrational number.

RHS is a rational number.

LHS ≠ RHS

∴ our assumption is wrong. 4 – 5√3 is an irrational number.

Leave a Comment

Your email address will not be published. Required fields are marked *

BOOK

Free Class