Prove that sinA/1 + cosA = 1 - cosA / sinA

Solution:

\(\frac{sinA}{1+cosA}=\frac{1-cosA}{sinA}\)

Multiplying and dividing L.H.S by (1-cosA)

\(\frac{sinA}{1+cosA}\times \frac{1-cosA}{1-cosA}\) \(\frac{sinA\times (1-cosA))}{1-cos^{2}A}=\frac{1-cosA}{sinA}\)

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