Solve -2x - 7-5x-9x - 3-4x- - 7-6

Given :[2x (7 5x)]/[9x (3+4x)] = 7/6[2x 7+5x]/[9x 3 4x] = 7/67x 7 /5x 3=7/6Cross multiply⇒ 6(7x 7) = 7(5x 3)⇒ 42x – 42 = 35x 21⇒ 7x = 21∴ x=3Hence, ...

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Byju's Answer

Standard VIII

Mathematics

Solving Linear Equations Using Transpose of Terms

Solve :[2x - ...

Question

Solve :
$\frac{[2 x - (7 - 5 x)]}{[9 x - (3 + 4 x)]} = \frac{7}{6}$

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Solution

Given :
$\frac{[2 x - (7 - 5 x)]}{[9 x - (3 + 4 x)]} = \frac{7}{6}$
$\frac{[2 x - 7 + 5 x]}{[9 x - 3 - 4 x]} = \frac{7}{6}$
$\frac{7 x - 7}{5 x - 3} = \frac{7}{6}$
Cross multiply
$\Rightarrow 6 (7 x - 7) = 7 (5 x - 3)$
$\Rightarrow 42 x - 42 = 35 x - 21$
$\Rightarrow 7 x = 21$
$∴ x = 3$
Hence, $x = 3$ is the correct answer.

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Similar questions

Solve the following equations and verify your answer :

$\frac{2 x - (7 - 5 x)}{9 x - (3 + 4 x)} = \frac{7}{6}$

Solve for $x$ : $\frac{2 x}{7} - 6 = 4$ .

Q. Solve

\frac{2 x - (7 - 5 x)}{9 x - (3 + 4 x)} = \frac{7}{6}

Q. Solve the following equation and verify your answer:

\frac{2 x - (7 - 5 x)}{9 x - (3 + 4 x)} = \frac{7}{6}

Solve the following equations for $x$ :

$(\frac{2 x + 3}{x + 1}) + 6 (\frac{x + 1}{2 x + 3}) = 7$

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Solve :[2x-(7-5x)][9x-(3+4x)]=76

Given :[2x-(7-5x)][9x-(3+4x)]=76[2x-7+5x][9x-3-4x]=767x-75x-3=76Cross multiply⇒6(7x-7)=7(5x-3)⇒42x–42=35x-21⇒7x=21∴x=3Hence, x=3 is the correct answer.

Solve :
$\frac{[2 x - (7 - 5 x)]}{[9 x - (3 + 4 x)]} = \frac{7}{6}$