Solve For X: Log3 X - Log32 = 1

Given:

[latex]log_{3}\; x – log_{3} \;2\; = \;1[/latex]


We need to solve for x.

[latex]log_{3}\; x\; = \;1\; + \;log_{3}\; 2.[/latex]


Since, 1 can be written as [latex]log_{3}\;3\; = \;1 [/latex] [latex]\Rightarrow log_{3} \;(3 * 2)\\\Rightarrow log_{3} \;6\\\Rightarrow xv = \;6[/latex]

Therefore, x = 6.


Explore more such questions and answers at BYJU’S.

Was this answer helpful?

 
   

0 (0)

(0)
(0)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question