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Question

Solve For x:

log3x-log32=1


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Solution

Logarithm equation :

log3x-log32=1

We need to solve for x

log3x=1+log32

Since, 1 can be written as log33=1

log3x=log33+log32

log3x=log33×2log3x=log36

x=6

Hence, the value of x is 6.


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