Solve The Following: 3/2x + 5/3 y = 7 And 9 - 10y = 14.

Sol:

Given:

[latex]\frac{3}{2}x + \frac{5}{3}y = 7— [1][/latex]

9x – 10y = 14 —[2]

Here:

[latex]a_{1} = \frac{3}{2}[/latex] [latex]b_{1} = \frac{3}{5}[/latex]

c1 = 7

a2 = 9

b2 = -10

c2 = 14

Thus,

[latex]\frac{a_{1}}{a_{2}}\\\Rightarrow \frac{3}{2 * 9}\\\Rightarrow \frac{3}{18}\\\Rightarrow \frac{1}{6}\\\Rightarrow \frac{b_{1}}{b_{2}} \\\Rightarrow \frac{5}{3 * (-10)}\\\Rightarrow \frac{5}{(-30)}\\\Rightarrow \frac{1}{-6}[/latex]

Therefore,[latex] \frac{a_{1}}{a_{2}} ≠ \frac{b_{1}}{b_{2}} [/latex]

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