Question

Solve the quadratic equations:

$x^2+x+1=0$.

Answer 1

Compute the required value:

We have,$x^2+x+1=0$

General form of quadratic equation: $a{x}^2+bx+c=0$

On comparing general form of equation with the given equation, we have

$a=1,b=1,c=1$

Let us find discriminant, $D$ in this case which is

$$\begin{gathered} D=b^2-4ac \\ ={\left(1\right)}^2-4\left(1\right)\left(1\right) \\ =1-4 \\ =-3 \end{gathered}$$

When, $D<0$, the roots are not real.

Hence, the solution is not real.