Solve x-2y=0; 3x+4y=20

Given: x-2y=0

3x+4y=20

We need to find the values of x and y

x-2y=0 ————-(i)

3x+4y=20————-(ii)

Multiplying Equation (i) by 2 we get

2x-2y=0———–(iii)

Solving equations (ii) and (iii) we get,

3x+4y=20

2x-4y=0

_________

5x=20

x=5

Substituting the value of x in equation (i) we get,

5-2y=0

-2y=-5

2y=5

y=5/2

Hence x= 5 and y = 5/2

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