the block shown in figure (5.11) has a mass m and descends with an acceleration a. the mass of the string below the point a is m. find the tension of the string at the point a and at the lower end

Let the tension in the string going over pulley be T

And the acceleration of mass m is a (upward direction)

For left side mass,

T−mg=ma

Or ,T=mg+ma

For right side masses,

5mg−T=5ma

Or ,T=5mg−5ma

From above equations,

mg+ma=5mg−5ma

Or ,6ma=4mg

Or ,a=2g/3

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