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Question

The bond angle in H2Ois104.5°. This fact can be explained with the help of ?


A

VSEPR theory

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B

Molecular orbital theory

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C

Electronegativity difference between Oxygen and Hydrogen atoms

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D

Presence of Hydrogen bond

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Solution

The correct option is A

VSEPR theory


Explanation for the correct option:

Option(A):VSEPR theory

  • VSEPR Theory is used to predict the shape of any given molecule from the electron pairs that surround the central atoms of the molecule.
  • According to this theory, the atoms tend to arrange themselves in a manner in which this electron pair repulsion is minimalized, which in turn determines the geometry and shape of the resulting molecule.
  • In the case of H2Othe Oxygen, the atom has 6 electrons of which two of them are bonded with a hydrogen atom leaving two lone pairs of electrons.
  • The presence of these 2 lone pairs represents the bond angle of H2Oto be 104.5°, which can be only explained by the valence shell electron pair repulsion theory (VSEPR).

Explanation for the incorrect option:

Option(B):Molecular orbital theory

  • The molecular orbital theory does not help in explaining the bond angle of any molecule.
  • hence, the given option is the incorrect one.

Option(C): Electronegativity difference between Oxygen and Hydrogen atoms

  • The electronegativity difference between Oxygen and Hydrogen atoms does not explain the bond angle in H2Ois104.5°.
  • Thus, the given option does not represent the correct option.

Option(D): Presence of Hydrogen bond

  • The bond angle in H2Ocan't be explained by the presence of a Hydrogen bond.
  • Hence, the given option does not coincide with the given option.

Hence, the given fact can be explained with the help of the VSEPR theory.


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