The bond order of B2 molecule is_______

Answer:

The bond order of B2 molecule is one.

Bond order

The bond order shows the number of chemical bonds present between a pair of atoms. The Bond Order Formula can be defined as half of the difference between the number of electrons in bonding orbitals and antibonding orbitals.

\(Bond\, order = \frac{1}{2}\left [ N_{b}-N_{a} \right ]\)

Where,

Nb = Number of bonding electrons

Na = Number of antibonding electrons

Bond order of B2 molecule

The atomic number of Boron (B) is 5, the electronic configuration of Boron is,

B (Z = 5) = 1s2 2s2 2p1

Bond order = 1/2 [Nb – Na]

Bond order = 1

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