The bond order of B2 molecule is_______


The bond order of the B2 molecule is one.

Bond order

The bond order shows the number of chemical bonds present between a pair of atoms. The Bond Order Formula can be defined as half of the difference between the number of electrons in bonding orbitals and antibonding orbitals.

\(\begin{array}{l}Bond\, order = \frac{1}{2}\left [ N_{b}-N_{a} \right ]\end{array} \)


Nb = Number of bonding electrons

Na = Number of antibonding electrons

Bond order of B2 molecule

The atomic number of Boron (B) is 5, the electronic configuration of Boron is,

B (Z = 5) = 1s2 2s2 2p1

Bond order = 1/2 [Nb – Na]

Bond order = 1

Explore more such questions and answers at BYJU’S.


Related Links:

Was this answer helpful?


2.5 (16)


Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *




App Now